An interesting Math problem…
If:
2 + 2 = 4,
3 + 2 = 5,
3 + 4 = 14,
4 + 2 = 18 and
5 + 3 = 40
What is 6 + 3?
I’ll announce the answer in a week. Post a comment below if you think you have the answer
UPDATE
So, after a week, JP was the only one to get the correct answer!
If:
2 + 2 = 4, (common multiple = 1)
3 + 2 = 5, (common multiple = 1)
3 + 4 = 14, (common multiple = 2)
4 + 2 = 18 and (common multiple = 3)
5 + 3 = 40 (common multiple = 5)
What is 6 + 3?
As you can see, the common multiple for each line of equation evaluates to a Fibonacci sequence (starting at 1), and the last common multiple was 5, so the next one will be 8, therefore:
6 + 3 = 9 * 8 = 72
| Print article | This entry was posted by Danny Kopping on June 9, 2009 at 2:42 pm, and is filed under Fun. Follow any responses to this post through RSS 2.0. You can leave a response or trackback from your own site. |
about 2 years ago
42!!!
about 2 years ago
Nope
about 2 years ago
*blackles*
about 2 years ago
Eeek, this makes my brain itch — how’s 72?
about 2 years ago
6 False^3 True^2+3
>.>
about 2 years ago
9
Previous violations of mathematical laws do not excuse future ones.
J.Ja